Python Snippets

Calculates the date of n days from the given date

• Use datetime.timedelta and the + operator to calculate the new datetime.datetime value after adding n days to d.
• Omit the second argument, d, to use a default value of datetime.today().

from datetime import datetime, timedelta

def add_days(n, d = datetime.today()):return d + timedelta(n)

from datetime import date

add_days(5, date(2020, 10, 25)) # date(2020, 10, 30)
add_days(-5, date(2020, 10, 25)) # date(2020, 10, 20)

Checks if all elements in a list are equal

• Use set() to eliminate duplicate elements and then use len() to check if length is 1.

def all_equal(lst):return len(set(lst)) == 1

all_equal([1, 2, 3, 4, 5, 6]) # False
all_equal([1, 1, 1, 1]) # True

Checks if all the values in a list are unique

• Use set() on the given list to keep only unique occurrences.
• Use len() to compare the length of the unique values to the original list.

def all_unique(lst):return len(lst) == len(set(lst))

x = [1, 2, 3, 4, 5, 6]
y = [1, 2, 2, 3, 4, 5]
all_unique(x) # True
all_unique(y) # False

Generates a list of numbers in the arithmetic progression starting with the given positive integer and up to the specified limit

• Use range() and list() with the appropriate start, step and end values.

def arithmetic_progression(n, lim):return list(range(n, lim + 1, n))

arithmetic_progression(5, 25) # [5, 10, 15, 20, 25]

Calculates the average of two or more numbers

• Use sum() to sum all of the args provided, divide by len().

def average(*args):return sum(args, 0.0) / len(args)

average(*[1, 2, 3]) # 2.0
average(1, 2, 3) # 2.0

Calculates the average of a list, after mapping each element to a value using the provided function

• Use map() to map each element to the value returned by fn.
• Use sum() to sum all of the mapped values, divide by len(lst).
• Omit the last argument, fn, to use the default identity function.

def average_by(lst, fn = lambda x: x):return sum(map(fn, lst), 0.0) / len(lst)

average_by([{ 'n': 4 }, { 'n': 2 }, { 'n': 8 }, { 'n': 6 }], lambda x: x['n'])# 5.0

Splits values into two groups, based on the result of the given filter list

• Use a list comprehension and zip() to add elements to groups, based on filter.
• If filter has a truthy value for any element, add it to the first group, otherwise add it to the second group.

def bifurcate(lst, filter):return [[x for x, flag in zip(lst, filter) if flag],[x for x, flag in zip(lst, filter) if not flag]]

bifurcate(['beep', 'boop', 'foo', 'bar'], [True, True, False, True])# [ ['beep', 'boop', 'bar'], ['foo'] ]

Splits values into two groups, based on the result of the given filtering function

• Use a list comprehension to add elements to groups, based on the value returned by fn for each element.
• If fn returns a truthy value for any element, add it to the first group, otherwise add it to the second group.

def bifurcate_by(lst, fn):return [[x for x in lst if fn(x)],[x for x in lst if not fn(x)]]

bifurcate_by(['beep', 'boop', 'foo', 'bar'], lambda x: x[0] == 'b')# [ ['beep', 'boop', 'bar'], ['foo'] ]

Calculates the number of ways to choose k items from n items without repetition and without order

• Use math.comb() to calculate the binomial coefficient.

from math import comb

def binomial_coefficient(n, k):return comb(n, k)

binomial_coefficient(8, 2) # 28

Returns the length of a string in bytes

• Use str.encode('utf-8') to encode the given string and return its length.

def byte_size(s):return len(s.encode('utf-8'))

byte_size('😀') # 4
byte_size('Hello World') # 11

Converts a string to camelcase

• Use re.sub() to replace any - or _ with a space, using the regexp r"(_|-)+".
• Use str.title() to capitalize the first letter of each word and convert the rest to lowercase.
• Finally, use str.replace() to remove spaces between words.

from re import sub

def camel(s):
  s = sub(r"(_|-)+", " ", s).title().replace(" ", "")return ''.join([s[0].lower(), s[1:]])

camel('some_database_field_name') # 'someDatabaseFieldName'
camel('Some label that needs to be camelized')# 'someLabelThatNeedsToBeCamelized'
camel('some-javascript-property') # 'someJavascriptProperty'
camel('some-mixed_string with spaces_underscores-and-hyphens')# 'someMixedStringWithSpacesUnderscoresAndHyphens'

Capitalizes the first letter of a string

• Use list slicing and str.upper() to capitalize the first letter of the string.
• Use str.join() to combine the capitalized first letter with the rest of the characters.
• Omit the lower_rest parameter to keep the rest of the string intact, or set it to True to convert to lowercase.

def capitalize(s, lower_rest = False):return ''.join([s[:1].upper(), (s[1:].lower() if lower_rest else s[1:])])

capitalize('fooBar') # 'FooBar'
capitalize('fooBar', True) # 'Foobar'

Capitalizes the first letter of every word in a string

• Use str.title() to capitalize the first letter of every word in the string.

def capitalize_every_word(s):return s.title()

capitalize_every_word('hello world!') # 'Hello World!'

Casts the provided value as a list if it's not one

• Use isinstance() to check if the given value is enumerable.
• Return it by using list() or encapsulated in a list accordingly.

def cast_list(val):return list(val) if isinstance(val, (tuple, list, set, dict)) else [val]

cast_list('foo') # ['foo']
cast_list([1]) # [1]
cast_list(('foo', 'bar')) # ['foo', 'bar']

unlisted: true

Converts Celsius to Fahrenheit.

• Follow the conversion formula F = 1.8 * C + 32.

def celsius_to_fahrenheit(degrees):return ((degrees * 1.8) + 32)

celsius_to_fahrenheit(180) # 356.0

Creates a function that will invoke a predicate function for the specified property on a given object

• Return a lambda function that takes an object and applies the predicate function, fn to the specified property.

def check_prop(fn, prop):return lambda obj: fn(obj[prop])

check_age = check_prop(lambda x: x >= 18, 'age')
user = {'name': 'Mark', 'age': 18}
check_age(user) # True

Chunks a list into smaller lists of a specified size

• Use list() and range() to create a list of the desired size.
• Use map() on the list and fill it with splices of the given list.
• Finally, return the created list.

from math import ceil

def chunk(lst, size):return list(map(lambda x: lst[x * size:x * size + size],list(range(ceil(len(lst) / size)))))

chunk([1, 2, 3, 4, 5], 2) # [[1, 2], [3, 4], [5]]

Chunks a list into n smaller lists

• Use math.ceil() and len() to get the size of each chunk.
• Use list() and range() to create a new list of size n.
• Use map() to map each element of the new list to a chunk the length of size.
• If the original list can't be split evenly, the final chunk will contain the remaining elements.

from math import ceil

def chunk_into_n(lst, n):
  size = ceil(len(lst) / n)return list(map(lambda x: lst[x * size:x * size + size],list(range(n))))

chunk_into_n([1, 2, 3, 4, 5, 6, 7], 4) # [[1, 2], [3, 4], [5, 6], [7]]

Clamps num within the inclusive range specified by the boundary values

• If num falls within the range (a, b), return num.
• Otherwise, return the nearest number in the range.

def clamp_number(num, a, b):return max(min(num, max(a, b)), min(a, b))

clamp_number(2, 3, 5) # 3
clamp_number(1, -1, -5) # -1

Inverts a dictionary with non-unique hashable values

• Create a collections.defaultdict with list as the default value for each key.
• Use dictionary.items() in combination with a loop to map the values of the dictionary to keys using dict.append().
• Use dict() to convert the collections.defaultdict to a regular dictionary.

from collections import defaultdict

def collect_dictionary(obj):
  inv_obj = defaultdict(list)for key, value in obj.items():
    inv_obj[value].append(key)return dict(inv_obj)

ages = {'Peter': 10,'Isabel': 10,'Anna': 9,}
collect_dictionary(ages) # { 10: ['Peter', 'Isabel'], 9: ['Anna'] }

Combines two or more dictionaries, creating a list of values for each key

• Create a new collections.defaultdict with list as the default value for each key and loop over dicts.
• Use dict.append() to map the values of the dictionary to keys.
• Use dict() to convert the collections.defaultdict to a regular dictionary.

from collections import defaultdict

def combine_values(*dicts):
  res = defaultdict(list)for d in dicts:for key in d:
      res[key].append(d[key])return dict(res)

d1 = {'a': 1, 'b': 'foo', 'c': 400}
d2 = {'a': 3, 'b': 200, 'd': 400}

combine_values(d1, d2) # {'a': [1, 3], 'b': ['foo', 200], 'c': [400], 'd': [400]}

Removes falsy values from a list

• Use filter() to filter out falsy values (False, None, 0, and "").

def compact(lst):return list(filter(None, lst))

compact([0, 1, False, 2, '', 3, 'a', 's', 34]) # [ 1, 2, 3, 'a', 's', 34 ]

Performs right-to-left function composition

• Use functools.reduce() to perform right-to-left function composition.
• The last (rightmost) function can accept one or more arguments; the remaining functions must be unary.

from functools import reducedef compose(*fns):return reduce(lambda f, g: lambda *args: f(g(*args)), fns)

add5 = lambda x: x + 5
multiply = lambda x, y: x * y
multiply_and_add_5 = compose(add5, multiply)
multiply_and_add_5(5, 2) # 15

Performs left-to-right function composition

• Use functools.reduce() to perform left-to-right function composition.
• The first (leftmost) function can accept one or more arguments; the remaining functions must be unary.

from functools import reducedef compose_right(*fns):return reduce(lambda f, g: lambda *args: g(f(*args)), fns)

add = lambda x, y: x + y
square = lambda x: x * x
add_and_square = compose_right(add, square)
add_and_square(1, 2) # 9

Groups the elements of a list based on the given function and returns the count of elements in each group

• Use collections.defaultdict to initialize a dictionary.
• Use map() to map the values of the given list using the given function.
• Iterate over the map and increase the element count each time it occurs.

from collections import defaultdict

def count_by(lst, fn = lambda x: x):
  count = defaultdict(int)for val in map(fn, lst):
    count[val] += 1return dict(count)

from math import floor

count_by([6.1, 4.2, 6.3], floor) # {6: 2, 4: 1}
count_by(['one', 'two', 'three'], len) # {3: 2, 5: 1}

Counts the occurrences of a value in a list

• Use list.count() to count the number of occurrences of val in lst.

def count_occurrences(lst, val):return lst.count(val)

count_occurrences([1, 1, 2, 1, 2, 3], 1) # 3

Creates a list of partial sums

• Use itertools.accumulate() to create the accumulated sum for each element.
• Use list() to convert the result into a list.

from itertools import accumulate

def cumsum(lst):return list(accumulate(lst))

cumsum(range(0, 15, 3)) # [0, 3, 9, 18, 30]

Curries a function

• Use functools.partial() to return a new partial object which behaves like fn with the given arguments, args, partially applied.

from functools import partial

def curry(fn, *args):return partial(fn, *args)

add = lambda x, y: x + y
add10 = curry(add, 10)
add10(20) # 30

Creates a list of dates between start (inclusive) and end (not inclusive)

• Use datetime.timedelta.days to get the days between start and end.
• Use int() to convert the result to an integer and range() to iterate over each day.
• Use a list comprehension and datetime.timedelta() to create a list of datetime.date objects.

from datetime import timedelta, date

def daterange(start, end):return [start + timedelta(n) for n in range(int((end - start).days))]

from datetime import date

daterange(date(2020, 10, 1), date(2020, 10, 5))# [date(2020, 10, 1), date(2020, 10, 2), date(2020, 10, 3), date(2020, 10, 4)]

Calculates the date of n days ago from today

• Use datetime.date.today() to get the current day.
• Use datetime.timedelta to subtract n days from today's date.

from datetime import timedelta, date

def days_ago(n):return date.today() - timedelta(n)

days_ago(5) # date(2020, 10, 23)

Calculates the day difference between two dates

• Subtract start from end and use datetime.timedelta.days to get the day difference.

def days_diff(start, end):return (end - start).days

from datetime import date

days_diff(date(2020, 10, 25), date(2020, 10, 28)) # 3

Calculates the date of n days from today

• Use datetime.date.today() to get the current day.
• Use datetime.timedelta to add n days from today's date.

from datetime import timedelta, date

def days_from_now(n):return date.today() + timedelta(n)

days_from_now(5) # date(2020, 11, 02)

Decapitalizes the first letter of a string

• Use list slicing and str.lower() to decapitalize the first letter of the string.
• Use str.join() to combine the lowercase first letter with the rest of the characters.
• Omit the upper_rest parameter to keep the rest of the string intact, or set it to True to convert to uppercase.

def decapitalize(s, upper_rest = False):return ''.join([s[:1].lower(), (s[1:].upper() if upper_rest else s[1:])])

decapitalize('FooBar') # 'fooBar'
decapitalize('FooBar', True) # 'fOOBAR'

Deep flattens a list

• Use recursion.
• Use isinstance() with collections.abc.Iterable to check if an element is iterable.
• If it is iterable, apply deep_flatten() recursively, otherwise return [lst].

from collections.abc import Iterable

def deep_flatten(lst):return ([a for i in lst for a in
          deep_flatten(i)] if isinstance(lst, Iterable) else [lst])

deep_flatten([1, [2], [[3], 4], 5]) # [1, 2, 3, 4, 5]

Converts an angle from degrees to radians

• Use math.pi and the degrees to radians formula to convert the angle from degrees to radians.

from math import pi

def degrees_to_rads(deg):return (deg * pi) / 180.0

degrees_to_rads(180) # ~3.1416

Invokes the provided function after ms milliseconds

• Use time.sleep() to delay the execution of fn by ms / 1000 seconds.

from time import sleep

def delay(fn, ms, *args):
  sleep(ms / 1000)return fn(*args)

delay(lambda x: print(x), 1000, 'later') # prints 'later' after one second

Converts a dictionary to a list of tuples

• Use dict.items() and list() to get a list of tuples from the given dictionary.

def dict_to_list(d):return list(d.items())

d = {'one': 1, 'three': 3, 'five': 5, 'two': 2, 'four': 4}
dict_to_list(d)# [('one', 1), ('three', 3), ('five', 5), ('two', 2), ('four', 4)]

Calculates the difference between two iterables, without filtering duplicate values

• Create a set from b.
• Use a list comprehension on a to only keep values not contained in the previously created set, _b.

def difference(a, b):
  _b = set(b)return [item for item in a if item not in _b]

difference([1, 2, 3], [1, 2, 4]) # [3]

Returns the difference between two lists, after applying the provided function to each list element of both

• Create a set, using map() to apply fn to each element in b.
• Use a list comprehension in combination with fn on a to only keep values not contained in the previously created set, _b.

def difference_by(a, b, fn):
  _b = set(map(fn, b))return [item for item in a if fn(item) not in _b]

from math import floor

difference_by([2.1, 1.2], [2.3, 3.4], floor) # [1.2]
difference_by([{ 'x': 2 }, { 'x': 1 }], [{ 'x': 1 }], lambda v : v['x'])# [ { x: 2 } ]

Converts a number to a list of digits

• Use map() combined with int on the string representation of n and return a list from the result.

def digitize(n):return list(map(int, str(n)))

digitize(123) # [1, 2, 3]

Returns a list with n elements removed from the left

• Use slice notation to remove the specified number of elements from the left.
• Omit the last argument, n, to use a default value of 1.

def drop(a, n = 1):return a[n:]

drop([1, 2, 3]) # [2, 3]
drop([1, 2, 3], 2) # [3]
drop([1, 2, 3], 42) # []

Returns a list with n elements removed from the right

• Use slice notation to remove the specified number of elements from the right.
• Omit the last argument, n, to use a default value of 1.

def drop_right(a, n = 1):return a[:-n]

drop_right([1, 2, 3]) # [1, 2]
drop_right([1, 2, 3], 2) # [1]
drop_right([1, 2, 3], 42) # []

Checks if the provided function returns True for every element in the list

• Use all() in combination with map() and fn to check if fn returns True for all elements in the list.

def every(lst, fn = lambda x: x):return all(map(fn, lst))

every([4, 2, 3], lambda x: x > 1) # True
every([1, 2, 3]) # True

Returns every nth element in a list

• Use slice notation to create a new list that contains every nth element of the given list.

def every_nth(lst, nth):return lst[nth - 1::nth]

every_nth([1, 2, 3, 4, 5, 6], 2) # [ 2, 4, 6 ]

Calculates the factorial of a number

• Use recursion.
• If num is less than or equal to 1, return 1.
• Otherwise, return the product of num and the factorial of num - 1.
• Throws an exception if num is a negative or a floating point number.

def factorial(num):if not ((num >= 0) and (num % 1 == 0)):raise Exception("Number can't be floating point or negative.")return 1 if num == 0 else num * factorial(num - 1)

factorial(6) # 720

unlisted: true

Converts Fahrenheit to Celsius.

• Follow the conversion formula C = (F - 32) * 5/9.

def fahrenheit_to_celsius(degrees):return ((degrees - 32) * 5/9)

fahrenheit_to_celsius(77) # 25.0

Generates a list, containing the Fibonacci sequence, up until the nth term

• Starting with 0 and 1, use list.append() to add the sum of the last two numbers of the list to the end of the list, until the length of the list reaches n.
• If n is less or equal to 0, return a list containing 0.

def fibonacci(n):if n <= 0:return [0]
  sequence = [0, 1]while len(sequence) <= n:
    next_value = sequence[len(sequence) - 1] + sequence[len(sequence) - 2]
    sequence.append(next_value)return sequence

fibonacci(7) # [0, 1, 1, 2, 3, 5, 8, 13]

Creates a list with the non-unique values filtered out

• Use collections.Counter to get the count of each value in the list.
• Use a list comprehension to create a list containing only the unique values.

from collections import Counter

def filter_non_unique(lst):return [item for item, count in Counter(lst).items() if count == 1]

filter_non_unique([1, 2, 2, 3, 4, 4, 5]) # [1, 3, 5]

Creates a list with the unique values filtered out

• Use collections.Counter to get the count of each value in the list.
• Use a list comprehension to create a list containing only the non-unique values.

from collections import Counter

def filter_unique(lst):return [item for item, count in Counter(lst).items() if count > 1]

filter_unique([1, 2, 2, 3, 4, 4, 5]) # [2, 4]

Finds the value of the first element in the given list that satisfies the provided testing function

• Use a list comprehension and next() to return the first element in lst for which fn returns True.

def find(lst, fn):return next(x for x in lst if fn(x))

find([1, 2, 3, 4], lambda n: n % 2 == 1) # 1

Finds the index of the first element in the given list that satisfies the provided testing function

• Use a list comprehension, enumerate() and next() to return the index of the first element in lst for which fn returns True.

def find_index(lst, fn):return next(i for i, x in enumerate(lst) if fn(x))

find_index([1, 2, 3, 4], lambda n: n % 2 == 1) # 0

Finds the indexes of all elements in the given list that satisfy the provided testing function

• Use enumerate() and a list comprehension to return the indexes of the all element in lst for which fn returns True.

def find_index_of_all(lst, fn):return [i for i, x in enumerate(lst) if fn(x)]

find_index_of_all([1, 2, 3, 4], lambda n: n % 2 == 1) # [0, 2]

Finds the first key in the provided dictionary that has the given value

• Use dictionary.items() and next() to return the first key that has a value equal to val.

def find_key(dict, val):return next(key for key, value in dict.items() if value == val)

ages = {'Peter': 10,'Isabel': 11,'Anna': 9,}
find_key(ages, 11) # 'Isabel'

Finds all keys in the provided dictionary that have the given value

• Use dictionary.items(), a generator and list() to return all keys that have a value equal to val.

def find_keys(dict, val):return list(key for key, value in dict.items() if value == val)

ages = {'Peter': 10,'Isabel': 11,'Anna': 10,}
find_keys(ages, 10) # [ 'Peter', 'Anna' ]

Finds the value of the last element in the given list that satisfies the provided testing function

• Use a list comprehension and next() to return the last element in lst for which fn returns True.

def find_last(lst, fn):return next(x for x in lst[::-1] if fn(x))

find_last([1, 2, 3, 4], lambda n: n % 2 == 1) # 3

Finds the index of the last element in the given list that satisfies the provided testing function

• Use a list comprehension, enumerate() and next() to return the index of the last element in lst for which fn returns True.

def find_last_index(lst, fn):return len(lst) - 1 - next(i for i, x in enumerate(lst[::-1]) if fn(x))

find_last_index([1, 2, 3, 4], lambda n: n % 2 == 1) # 2

Finds the items that are parity outliers in a given list

• Use collections.Counter with a list comprehension to count even and odd values in the list.
• Use collections.Counter.most_common() to get the most common parity.
• Use a list comprehension to find all elements that do not match the most common parity.

from collections import Counter

def find_parity_outliers(nums):return [
    x for x in nums
    if x % 2 != Counter([n % 2 for n in nums]).most_common()[0][0]]

find_parity_outliers([1, 2, 3, 4, 6]) # [1, 3]

Flattens a list of lists once

• Use a list comprehension to extract each value from sub-lists in order.

def flatten(lst):return [x for y in lst for x in y]

flatten([[1, 2, 3, 4], [5, 6, 7, 8]]) # [1, 2, 3, 4, 5, 6, 7, 8]

Executes the provided function once for each list element

• Use a for loop to execute fn for each element in itr.

def for_each(itr, fn):for el in itr:
    fn(el)

for_each([1, 2, 3], print) # 1 2 3

Executes the provided function once for each list element, starting from the list's last element

• Use a for loop in combination with slice notation to execute fn for each element in itr, starting from the last one.

def for_each_right(itr, fn):for el in itr[::-1]:
    fn(el)

for_each_right([1, 2, 3], print) # 3 2 1

Creates a dictionary with the unique values of a list as keys and their frequencies as the values

• Use collections.defaultdict() to store the frequencies of each unique element.
• Use dict() to return a dictionary with the unique elements of the list as keys and their frequencies as the values.

from collections import defaultdict

def frequencies(lst):
  freq = defaultdict(int)for val in lst:
    freq[val] += 1return dict(freq)

frequencies(['a', 'b', 'a', 'c', 'a', 'a', 'b']) # { 'a': 4, 'b': 2, 'c': 1 }

Converts a date from its ISO-8601 representation

• Use datetime.datetime.fromisoformat() to convert the given ISO-8601 date to a datetime.datetime object.

from datetime import datetime

def from_iso_date(d):return datetime.fromisoformat(d)

from_iso_date('2020-10-28T12:30:59.000000') # 2020-10-28 12:30:59

Calculates the greatest common divisor of a list of numbers

• Use functools.reduce() and math.gcd() over the given list.

from functools import reducefrom math import gcd as _gcd

def gcd(numbers):return reduce(_gcd, numbers)

gcd([8, 36, 28]) # 4

Initializes a list containing the numbers in the specified range where start and end are inclusive and the ratio between two terms is step

Returns an error if step equals 1.

• Use range(), math.log() and math.floor() and a list comprehension to create a list of the appropriate length, applying the step for each element.
• Omit the second argument, start, to use a default value of 1.
• Omit the third argument, step, to use a default value of 2.

from math import floor, log

def geometric_progression(end, start=1, step=2):return [start * step ** i for i in range(floor(log(end / start)/ log(step)) + 1)]

geometric_progression(256) # [1, 2, 4, 8, 16, 32, 64, 128, 256]
geometric_progression(256, 3) # [3, 6, 12, 24, 48, 96, 192]
geometric_progression(256, 1, 4) # [1, 4, 16, 64, 256]

Retrieves the value of the nested key indicated by the given selector list from a dictionary or list

• Use functools.reduce() to iterate over the selectors list.
• Apply operator.getitem() for each key in selectors, retrieving the value to be used as the iteratee for the next iteration.

from functools import reducefrom operator import getitem

def get(d, selectors):return reduce(getitem, selectors, d)

users = {'freddy': {'name': {'first': 'fred','last': 'smith'},'postIds': [1, 2, 3]}}
get(users, ['freddy', 'name', 'last']) # 'smith'
get(users, ['freddy', 'postIds', 1]) # 2

Groups the elements of a list based on the given function

• Use collections.defaultdict to initialize a dictionary.
• Use fn in combination with a for loop and dict.append() to populate the dictionary.
• Use dict() to convert it to a regular dictionary.

from collections import defaultdict

def group_by(lst, fn):
  d = defaultdict(list)for el in lst:
    d[fn(el)].append(el)return dict(d)

from math import floor

group_by([6.1, 4.2, 6.3], floor) # {4: [4.2], 6: [6.1, 6.3]}
group_by(['one', 'two', 'three'], len) # {3: ['one', 'two'], 5: ['three']}

Calculates the Hamming distance between two values

• Use the XOR operator (^) to find the bit difference between the two numbers.
• Use bin() to convert the result to a binary string.
• Convert the string to a list and use count() of str class to count and return the number of 1s in it.

def hamming_distance(a, b):return bin(a ^ b).count('1')

hamming_distance(2, 3) # 1

Checks if there are duplicate values in a flat list

• Use set() on the given list to remove duplicates, compare its length with the length of the list.

def has_duplicates(lst):return len(lst) != len(set(lst))

x = [1, 2, 3, 4, 5, 5]
y = [1, 2, 3, 4, 5]
has_duplicates(x) # True
has_duplicates(y) # False

Checks if two lists contain the same elements regardless of order

• Use set() on the combination of both lists to find the unique values.
• Iterate over them with a for loop comparing the count() of each unique value in each list.
• Return False if the counts do not match for any element, True otherwise.

def have_same_contents(a, b):for v in set(a + b):if a.count(v) != b.count(v):return Falsereturn True

have_same_contents([1, 2, 4], [2, 4, 1]) # True

Returns the head of a list

• Use lst[0] to return the first element of the passed list.

def head(lst):return lst[0]

head([1, 2, 3]) # 1

Converts a hexadecimal color code to a tuple of integers corresponding to its RGB components

• Use a list comprehension in combination with int() and list slice notation to get the RGB components from the hexadecimal string.
• Use tuple() to convert the resulting list to a tuple.

def hex_to_rgb(hex):return tuple(int(hex[i:i+2], 16) for i in (0, 2, 4))

hex_to_rgb('FFA501') # (255, 165, 1)

Checks if the given number falls within the given range

• Use arithmetic comparison to check if the given number is in the specified range.
• If the second parameter, end, is not specified, the range is considered to be from 0 to start.

def in_range(n, start, end = 0):return start <= n <= end if end >= start else end <= n <= start

in_range(3, 2, 5) # True
in_range(3, 4) # True
in_range(2, 3, 5) # False
in_range(3, 2) # False

Checks if all the elements in values are included in lst

• Check if every value in values is contained in lst using a for loop.
• Return False if any one value is not found, True otherwise.

def includes_all(lst, values):for v in values:if v not in lst:return Falsereturn True

includes_all([1, 2, 3, 4], [1, 4]) # True
includes_all([1, 2, 3, 4], [1, 5]) # False

Checks if any element in values is included in lst

• Check if any value in values is contained in lst using a for loop.
• Return True if any one value is found, False otherwise.

def includes_any(lst, values):for v in values:if v in lst:return Truereturn False

includes_any([1, 2, 3, 4], [2, 9]) # True
includes_any([1, 2, 3, 4], [8, 9]) # False

Returns a list of indexes of all the occurrences of an element in a list

• Use enumerate() and a list comprehension to check each element for equality with value and adding i to the result.

def index_of_all(lst, value):return [i for i, x in enumerate(lst) if x == value]

index_of_all([1, 2, 1, 4, 5, 1], 1) # [0, 2, 5]
index_of_all([1, 2, 3, 4], 6) # []

Returns all the elements of a list except the last one

• Use lst[:-1] to return all but the last element of the list.

def initial(lst):return lst[:-1]

initial([1, 2, 3]) # [1, 2]

Initializes a 2D list of given width and height and value

• Use a list comprehension and range() to generate h rows where each is a list with length h, initialized with val.
• Omit the last argument, val, to set the default value to None.

def initialize_2d_list(w, h, val = None):return [[val for x in range(w)] for y in range(h)]

initialize_2d_list(2, 2, 0) # [[0, 0], [0, 0]]

Initializes a list containing the numbers in the specified range where start and end are inclusive with their common difference step

• Use list() and range() to generate a list of the appropriate length, filled with the desired values in the given range.
• Omit start to use the default value of 0.
• Omit step to use the default value of 1.

def initialize_list_with_range(end, start = 0, step = 1):return list(range(start, end + 1, step))

initialize_list_with_range(5) # [0, 1, 2, 3, 4, 5]
initialize_list_with_range(7, 3) # [3, 4, 5, 6, 7]
initialize_list_with_range(9, 0, 2) # [0, 2, 4, 6, 8]

Initializes and fills a list with the specified value

• Use a list comprehension and range() to generate a list of length equal to n, filled with the desired values.
• Omit val to use the default value of 0.

def initialize_list_with_values(n, val = 0):return [val for x in range(n)]

initialize_list_with_values(5, 2) # [2, 2, 2, 2, 2]

Returns a list of elements that exist in both lists

• Create a set from a and b.
• Use the built-in set operator & to only keep values contained in both sets, then transform the set back into a list.

def intersection(a, b):
  _a, _b = set(a), set(b)return list(_a & _b)

intersection([1, 2, 3], [4, 3, 2]) # [2, 3]

Returns a list of elements that exist in both lists, after applying the provided function to each list element of both

• Create a set, using map() to apply fn to each element in b.
• Use a list comprehension in combination with fn on a to only keep values contained in both lists.

def intersection_by(a, b, fn):
  _b = set(map(fn, b))return [item for item in a if fn(item) in _b]

from math import floor

intersection_by([2.1, 1.2], [2.3, 3.4], floor) # [2.1]

Inverts a dictionary with unique hashable values

• Use dictionary.items() in combination with a list comprehension to create a new dictionary with the values and keys inverted.

def invert_dictionary(obj):return { value: key for key, value in obj.items() }

ages = {'Peter': 10,'Isabel': 11,'Anna': 9,}
invert_dictionary(ages) # { 10: 'Peter', 11: 'Isabel', 9: 'Anna' }

Checks if a string is an anagram of another string (case-insensitive, ignores spaces, punctuation and special characters)

• Use str.isalnum() to filter out non-alphanumeric characters, str.lower() to transform each character to lowercase.
• Use collections.Counter to count the resulting characters for each string and compare the results.

from collections import Counter

def is_anagram(s1, s2):return Counter(
    c.lower() for c in s1 if c.isalnum()) == Counter(
    c.lower() for c in s2 if c.isalnum())

is_anagram('#anagram', 'Nag a ram!')  # True

Checks if the elements of the first list are contained in the second one regardless of order

• Use count() to check if any value in a has more occurrences than it has in b.
• Return False if any such value is found, True otherwise.

def is_contained_in(a, b):for v in set(a):if a.count(v) > b.count(v):return Falsereturn True

is_contained_in([1, 4], [2, 4, 1]) # True

unlisted: true

Checks if the first numeric argument is divisible by the second one.

• Use the modulo operator (%) to check if the remainder is equal to 0.

def is_divisible(dividend, divisor):return dividend % divisor == 0

is_divisible(6, 3) # True

unlisted: true

Checks if the given number is even.

• Check whether a number is odd or even using the modulo (%) operator.
• Return True if the number is even, False if the number is odd.

def is_even(num):return num % 2 == 0

is_even(3) # False

unlisted: true

Checks if the given number is odd.

• Checks whether a number is even or odd using the modulo (%) operator.
• Returns True if the number is odd, False if the number is even.

def is_odd(num):return num % 2 != 0

is_odd(3) # True

Checks if the provided integer is a prime number

• Return False if the number is 0, 1, a negative number or a multiple of 2.
• Use all() and range() to check numbers from 3 to the square root of the given number.
• Return True if none divides the given number, False otherwise.

from math import sqrt

def is_prime(n):if n <= 1 or (n % 2 == 0 and n > 2):return Falsereturn all(n % i for i in range(3, int(sqrt(n)) + 1, 2))

is_prime(11) # True

Checks if the given date is a weekday

• Use datetime.datetime.weekday() to get the day of the week as an integer.
• Check if the day of the week is less than or equal to 4.
• Omit the second argument, d, to use a default value of datetime.today().

from datetime import datetime

def is_weekday(d = datetime.today()):return d.weekday() <= 4

from datetime import date

is_weekday(date(2020, 10, 25)) # False
is_weekday(date(2020, 10, 28)) # True

Checks if the given date is a weekend

• Use datetime.datetime.weekday() to get the day of the week as an integer.
• Check if the day of the week is greater than 4.
• Omit the second argument, d, to use a default value of datetime.today().

from datetime import datetime

def is_weekend(d = datetime.today()):return d.weekday() > 4

from datetime import date

is_weekend(date(2020, 10, 25)) # True
is_weekend(date(2020, 10, 28)) # False

Converts a string to kebab case

• Use re.sub() to replace any - or _ with a space, using the regexp r"(_|-)+".
• Use re.sub() to match all words in the string, str.lower() to lowercase them.
• Finally, use str.join() to combine all word using - as the separator.

from re import sub

def kebab(s):return '-'.join(
    sub(r"(\s|_|-)+"," ",
    sub(r"[A-Z]{2,}(?=[A-Z][a-z]+[0-9]*|\b)|[A-Z]?[a-z]+[0-9]*|[A-Z]|[0-9]+",lambda mo: ' ' + mo.group(0).lower(), s)).split())

kebab('camelCase') # 'camel-case'
kebab('some text') # 'some-text'
kebab('some-mixed_string With spaces_underscores-and-hyphens')# 'some-mixed-string-with-spaces-underscores-and-hyphens'
kebab('AllThe-small Things') # 'all-the-small-things'

Checks if the given key exists in a dictionary

• Use the in operator to check if d contains key.

def key_in_dict(d, key):return (key in d)

d = {'one': 1, 'three': 3, 'five': 5, 'two': 2, 'four': 4}
key_in_dict(d, 'three') # True

Finds the key of the maximum value in a dictionary

• Use max() with the key parameter set to dict.get() to find and return the key of the maximum value in the given dictionary.

def key_of_max(d):return max(d, key = d.get)

key_of_max({'a':4, 'b':0, 'c':13}) # c

Finds the key of the minimum value in a dictionary

• Use min() with the key parameter set to dict.get() to find and return the key of the minimum value in the given dictionary.

def key_of_min(d):return min(d, key = d.get)

key_of_min({'a':4, 'b':0, 'c':13}) # b

Creates a flat list of all the keys in a flat dictionary

• Use dict.keys() to return the keys in the given dictionary.
• Return a list() of the previous result.

def keys_only(flat_dict):return list(flat_dict.keys())

ages = {'Peter': 10,'Isabel': 11,'Anna': 9,}
keys_only(ages) # ['Peter', 'Isabel', 'Anna']

unlisted: true

Converts kilometers to miles.

• Follows the conversion formula mi = km * 0.621371.

def km_to_miles(km):return km * 0.621371

km_to_miles(8.1) # 5.0331051

Returns the last element in a list

• Use lst[-1] to return the last element of the passed list.

def last(lst):return lst[-1]

last([1, 2, 3]) # 3

Returns the least common multiple of a list of numbers

• Use functools.reduce(), math.gcd() and lcm(x,y) = x * y / gcd(x,y) over the given list.

from functools import reducefrom math import gcd

def lcm(numbers):return reduce((lambda x, y: int(x * y / gcd(x, y))), numbers)

lcm([12, 7]) # 84
lcm([1, 3, 4, 5]) # 60

Takes any number of iterable objects or objects with a length property and returns the longest one

• Use max() with len() as the key to return the item with the greatest length.
• If multiple objects have the same length, the first one will be returned.

def longest_item(*args):return max(args, key = len)

longest_item('this', 'is', 'a', 'testcase') # 'testcase'
longest_item([1, 2, 3], [1, 2], [1, 2, 3, 4, 5]) # [1, 2, 3, 4, 5]
longest_item([1, 2, 3], 'foobar') # 'foobar'

Maps the values of a list to a dictionary using a function, where the key-value pairs consist of the original value as the key and the result of the function as the value

• Use map() to apply fn to each value of the list.
• Use zip() to pair original values to the values produced by fn.
• Use dict() to return an appropriate dictionary.

def map_dictionary(itr, fn):return dict(zip(itr, map(fn, itr)))

map_dictionary([1, 2, 3], lambda x: x * x) # { 1: 1, 2: 4, 3: 9 }

Creates a dictionary with the same keys as the provided dictionary and values generated by running the provided function for each value

• Use dict.items() to iterate over the dictionary, assigning the values produced by fn to each key of a new dictionary.

def map_values(obj, fn):return dict((k, fn(v)) for k, v in obj.items())

users = {'fred': { 'user': 'fred', 'age': 40 },'pebbles': { 'user': 'pebbles', 'age': 1 }}
map_values(users, lambda u : u['age']) # {'fred': 40, 'pebbles': 1}

Returns the maximum value of a list, after mapping each element to a value using the provided function

• Use map() with fn to map each element to a value using the provided function.
• Use max() to return the maximum value.

def max_by(lst, fn):return max(map(fn, lst))

max_by([{ 'n': 4 }, { 'n': 2 }, { 'n': 8 }, { 'n': 6 }], lambda v : v['n']) # 8

Returns the index of the element with the maximum value in a list

• Use max() and list.index() to get the maximum value in the list and return its index.

def max_element_index(arr):return arr.index(max(arr))

max_element_index([5, 8, 9, 7, 10, 3, 0]) # 4

Returns the n maximum elements from the provided list

• Use sorted() to sort the list.
• Use slice notation to get the specified number of elements.
• Omit the second argument, n, to get a one-element list.
• If n is greater than or equal to the provided list's length, then return the original list (sorted in descending order).

def max_n(lst, n = 1):return sorted(lst, reverse = True)[:n]

max_n([1, 2, 3]) # [3]
max_n([1, 2, 3], 2) # [3, 2]

Finds the median of a list of numbers

• Sort the numbers of the list using list.sort().
• Find the median, which is either the middle element of the list if the list length is odd or the average of the two middle elements if the list length is even.
• statistics.median() provides similar functionality to this snippet.

def median(list):list.sort()
  list_length = len(list)if list_length % 2 == 0:return (list[int(list_length / 2) - 1] + list[int(list_length / 2)]) / 2return float(list[int(list_length / 2)])

median([1, 2, 3]) # 2.0
median([1, 2, 3, 4]) # 2.5

Merges two or more lists into a list of lists, combining elements from each of the input lists based on their positions

• Use max() combined with a list comprehension to get the length of the longest list in the arguments.
• Use range() in combination with the max_length variable to loop as many times as there are elements in the longest list.
• If a list is shorter than max_length, use fill_value for the remaining items (defaults to None).
• zip() and itertools.zip_longest() provide similar functionality to this snippet.

def merge(*args, fill_value = None):
  max_length = max([len(lst) for lst in args])
  result = []for i in range(max_length):
    result.append([
      args[k][i] if i < len(args[k]) else fill_value for k in range(len(args))])return result

merge(['a', 'b'], [1, 2], [True, False]) # [['a', 1, True], ['b', 2, False]]
merge(['a'], [1, 2], [True, False]) # [['a', 1, True], [None, 2, False]]
merge(['a'], [1, 2], [True, False], fill_value = '_')# [['a', 1, True], ['_', 2, False]]

Merges two or more dictionaries

• Create a new dict and loop over dicts, using dictionary.update() to add the key-value pairs from each one to the result.

def merge_dictionaries(*dicts):
  res = dict()for d in dicts:
    res.update(d)return res

ages_one = {'Peter': 10,'Isabel': 11,}
ages_two = {'Anna': 9}
merge_dictionaries(ages_one, ages_two)# { 'Peter': 10, 'Isabel': 11, 'Anna': 9 }

unlisted: true

Converts miles to kilometers.

• Follows the conversion formula km = mi * 1.609344.

def miles_to_km(miles):return miles * 1.609344

miles_to_km(5.03) # 8.09500032

Returns the minimum value of a list, after mapping each element to a value using the provided function

• Use map() with fn to map each element to a value using the provided function.
• Use min() to return the minimum value.

def min_by(lst, fn):return min(map(fn, lst))

min_by([{ 'n': 4 }, { 'n': 2 }, { 'n': 8 }, { 'n': 6 }], lambda v : v['n']) # 2

Returns the index of the element with the minimum value in a list

• Use min() and list.index() to obtain the minimum value in the list and then return its index.

def min_element_index(arr):return arr.index(min(arr))

min_element_index([3, 5, 2, 6, 10, 7, 9]) # 2

Returns the n minimum elements from the provided list

• Use sorted() to sort the list.
• Use slice notation to get the specified number of elements.
• Omit the second argument, n, to get a one-element list.
• If n is greater than or equal to the provided list's length, then return the original list (sorted in ascending order).

def min_n(lst, n = 1):return sorted(lst, reverse = False)[:n]

min_n([1, 2, 3]) # [1]
min_n([1, 2, 3], 2) # [1, 2]

Calculates the month difference between two dates

• Subtract start from end and use datetime.timedelta.days to get the day difference.
• Divide by 30 and use math.ceil() to get the difference in months (rounded up).

from math import ceil

def months_diff(start, end):return ceil((end - start).days / 30)

from datetime import date

months_diff(date(2020, 10, 28), date(2020, 11, 25)) # 1

Returns the most frequent element in a list

• Use set() to get the unique values in lst.
• Use max() to find the element that has the most appearances.

def most_frequent(lst):return max(set(lst), key = lst.count)

most_frequent([1, 2, 1, 2, 3, 2, 1, 4, 2]) #2

Generates a string with the given string value repeated n number of times

• Repeat the string n times, using the * operator.

def n_times_string(s, n):return (s * n)

n_times_string('py', 4) #'pypypypy'

Checks if the provided function returns True for at least one element in the list

• Use all() and fn to check if fn returns False for all the elements in the list.

def none(lst, fn = lambda x: x):return all(not fn(x) for x in lst)

none([0, 1, 2, 0], lambda x: x >= 2 ) # False
none([0, 0, 0]) # True

Maps a number from one range to another range

• Return num mapped between outMin-outMax from inMin-inMax.

def num_to_range(num, inMin, inMax, outMin, outMax):return outMin + (float(num - inMin) / float(inMax - inMin) * (outMax
                  - outMin))

num_to_range(5, 0, 10, 0, 100) # 50.0

Moves the specified amount of elements to the end of the list

• Use slice notation to get the two slices of the list and combine them before returning.

def offset(lst, offset):return lst[offset:] + lst[:offset]

offset([1, 2, 3, 4, 5], 2) # [3, 4, 5, 1, 2]
offset([1, 2, 3, 4, 5], -2) # [4, 5, 1, 2, 3]

Pads a string on both sides with the specified character, if it's shorter than the specified length

• Use str.ljust() and str.rjust() to pad both sides of the given string.
• Omit the third argument, char, to use the whitespace character as the default padding character.

from math import floor

def pad(s, length, char = ' '):return s.rjust(floor((len(s) + length)/2), char).ljust(length, char)

pad('cat', 8) # '  cat   '
pad('42', 6, '0') # '004200'
pad('foobar', 3) # 'foobar'

Pads a given number to the specified length

• Use str.zfill() to pad the number to the specified length, after converting it to a string.

def pad_number(n, l):return str(n).zfill(l)

pad_number(1234, 6); # '001234'

Checks if the given string is a palindrome

• Use str.lower() and re.sub() to convert to lowercase and remove non-alphanumeric characters from the given string.
• Then, compare the new string with its reverse, using slice notation.

from re import sub

def palindrome(s):
  s = sub('[\W_]', '', s.lower())return s == s[::-1]

palindrome('taco cat') # True

Converts a list of dictionaries into a list of values corresponding to the specified key

• Use a list comprehension and dict.get() to get the value of key for each dictionary in lst.

def pluck(lst, key):return [x.get(key) for x in lst]

simpsons = [{ 'name': 'lisa', 'age': 8 },{ 'name': 'homer', 'age': 36 },{ 'name': 'marge', 'age': 34 },{ 'name': 'bart', 'age': 10 }]
pluck(simpsons, 'age') # [8, 36, 34, 10]

Returns the powerset of a given iterable

• Use list() to convert the given value to a list.
• Use range() and itertools.combinations() to create a generator that returns all subsets.
• Use itertools.chain.from_iterable() and list() to consume the generator and return a list.

from itertools import chain, combinations

def powerset(iterable):
  s = list(iterable)return list(chain.from_iterable(combinations(s, r) for r in range(len(s)+1)))

powerset([1, 2]) # [(), (1,), (2,), (1, 2)]

Converts an angle from radians to degrees

• Use math.pi and the radian to degree formula to convert the angle from radians to degrees.

from math import pi

def rads_to_degrees(rad):return (rad * 180.0) / pi

from math import pi

rads_to_degrees(pi / 2) # 90.0

Reverses a list or a string

• Use slice notation to reverse the list or string.

def reverse(itr):return itr[::-1]

reverse([1, 2, 3]) # [3, 2, 1]
reverse('snippet') # 'teppins'

Reverses a number

• Use str() to convert the number to a string, slice notation to reverse it and str.replace() to remove the sign.
• Use float() to convert the result to a number and math.copysign() to copy the original sign.

from math import copysign

def reverse_number(n):return copysign(float(str(n)[::-1].replace('-', '')), n)

reverse_number(981) # 189
reverse_number(-500) # -5
reverse_number(73.6) # 6.37
reverse_number(-5.23) # -32.5

Converts the values of RGB components to a hexadecimal color code

• Create a placeholder for a zero-padded hexadecimal value using '{:02X}' and copy it three times.
• Use str.format() on the resulting string to replace the placeholders with the given values.

def rgb_to_hex(r, g, b):return ('{:02X}' * 3).format(r, g, b)

rgb_to_hex(255, 165, 1) # 'FFA501'

Moves the specified amount of elements to the start of the list

• Use slice notation to get the two slices of the list and combine them before returning.

def roll(lst, offset):return lst[-offset:] + lst[:-offset]

roll([1, 2, 3, 4, 5], 2) # [4, 5, 1, 2, 3]
roll([1, 2, 3, 4, 5], -2) # [3, 4, 5, 1, 2]

Returns a random element from a list

• Use random.choice() to get a random element from lst.

from random import choice

def sample(lst):return choice(lst)

sample([3, 7, 9, 11]) # 9

Randomizes the order of the values of an list, returning a new list

• Uses the Fisher-Yates algorithm to reorder the elements of the list.
• random.shuffle provides similar functionality to this snippet.

from copy import deepcopy
from random import randint

def shuffle(lst):
  temp_lst = deepcopy(lst)
  m = len(temp_lst)while (m):
    m -= 1
    i = randint(0, m)
    temp_lst[m], temp_lst[i] = temp_lst[i], temp_lst[m]return temp_lst

foo = [1, 2, 3]
shuffle(foo) # [2, 3, 1], foo = [1, 2, 3]

Returns a list of elements that exist in both lists

• Use a list comprehension on a to only keep values contained in both lists.

def similarity(a, b):return [item for item in a if item in b]

similarity([1, 2, 3], [1, 2, 4]) # [1, 2]

Converts a string to a URL-friendly slug

• Use str.lower() and str.strip() to normalize the input string.
• Use re.sub() to to replace spaces, dashes and underscores with - and remove special characters.

import re

def slugify(s):
  s = s.lower().strip()
  s = re.sub(r'[^\w\s-]', '', s)
  s = re.sub(r'[\s_-]+', '-', s)
  s = re.sub(r'^-+|-+$', '', s)return s

slugify('Hello World!') # 'hello-world'

Converts a string to snake case

• Use re.sub() to match all words in the string, str.lower() to lowercase them.
• Use re.sub() to replace any - characters with spaces.
• Finally, use str.join() to combine all words using - as the separator.

from re import sub

def snake(s):return '_'.join(
    sub('([A-Z][a-z]+)', r' \1',
    sub('([A-Z]+)', r' \1',
    s.replace('-', ' '))).split()).lower()

snake('camelCase') # 'camel_case'
snake('some text') # 'some_text'
snake('some-mixed_string With spaces_underscores-and-hyphens')# 'some_mixed_string_with_spaces_underscores_and_hyphens'
snake('AllThe-small Things') # 'all_the_small_things'

Checks if the provided function returns True for at least one element in the list

• Use any() in combination with map() to check if fn returns True for any element in the list.

def some(lst, fn = lambda x: x):return any(map(fn, lst))

some([0, 1, 2, 0], lambda x: x >= 2 ) # True
some([0, 0, 1, 0]) # True

Sorts one list based on another list containing the desired indexes

• Use zip() and sorted() to combine and sort the two lists, based on the values of indexes.
• Use a list comprehension to get the first element of each pair from the result.
• Use the reverse parameter in sorted() to sort the dictionary in reverse order, based on the third argument.

def sort_by_indexes(lst, indexes, reverse=False):return [val for (_, val) in sorted(zip(indexes, lst), key=lambda x: \
          x[0], reverse=reverse)]

a = ['eggs', 'bread', 'oranges', 'jam', 'apples', 'milk']
b = [3, 2, 6, 4, 1, 5]
sort_by_indexes(a, b) # ['apples', 'bread', 'eggs', 'jam', 'milk', 'oranges']
sort_by_indexes(a, b, True)# ['oranges', 'milk', 'jam', 'eggs', 'bread', 'apples']

Sorts the given dictionary by key

• Use dict.items() to get a list of tuple pairs from d and sort it using sorted().
• Use dict() to convert the sorted list back to a dictionary.
• Use the reverse parameter in sorted() to sort the dictionary in reverse order, based on the second argument.

def sort_dict_by_key(d, reverse = False):return dict(sorted(d.items(), reverse = reverse))

d = {'one': 1, 'three': 3, 'five': 5, 'two': 2, 'four': 4}
sort_dict_by_key(d) # {'five': 5, 'four': 4, 'one': 1, 'three': 3, 'two': 2}
sort_dict_by_key(d, True)# {'two': 2, 'three': 3, 'one': 1, 'four': 4, 'five': 5}

Sorts the given dictionary by value

• Use dict.items() to get a list of tuple pairs from d and sort it using a lambda function and sorted().
• Use dict() to convert the sorted list back to a dictionary.
• Use the reverse parameter in sorted() to sort the dictionary in reverse order, based on the second argument.
• ⚠️ NOTICE: Dictionary values must be of the same type.

def sort_dict_by_value(d, reverse = False):return dict(sorted(d.items(), key = lambda x: x[1], reverse = reverse))

d = {'one': 1, 'three': 3, 'five': 5, 'two': 2, 'four': 4}
sort_dict_by_value(d) # {'one': 1, 'two': 2, 'three': 3, 'four': 4, 'five': 5}
sort_dict_by_value(d, True)# {'five': 5, 'four': 4, 'three': 3, 'two': 2, 'one': 1}

Splits a multiline string into a list of lines

• Use str.split() and '\n' to match line breaks and create a list.
• str.splitlines() provides similar functionality to this snippet.

def split_lines(s):return s.split('\n')

split_lines('This\nis a\nmultiline\nstring.\n')# ['This', 'is a', 'multiline', 'string.' , '']

Flattens a list, by spreading its elements into a new list

• Loop over elements, use list.extend() if the element is a list, list.append() otherwise.

def spread(arg):
  ret = []for i in arg:
    ret.extend(i) if isinstance(i, list) else ret.append(i)return ret

spread([1, 2, 3, [4, 5, 6], [7], 8, 9]) # [1, 2, 3, 4, 5, 6, 7, 8, 9]

Calculates the sum of a list, after mapping each element to a value using the provided function

• Use map() with fn to map each element to a value using the provided function.
• Use sum() to return the sum of the values.

def sum_by(lst, fn):return sum(map(fn, lst))

sum_by([{ 'n': 4 }, { 'n': 2 }, { 'n': 8 }, { 'n': 6 }], lambda v : v['n']) # 20

Returns the sum of the powers of all the numbers from start to end (both inclusive)

• Use range() in combination with a list comprehension to create a list of elements in the desired range raised to the given power.
• Use sum() to add the values together.
• Omit the second argument, power, to use a default power of 2.
• Omit the third argument, start, to use a default starting value of 1.

def sum_of_powers(end, power = 2, start = 1):return sum([(i) ** power for i in range(start, end + 1)])

sum_of_powers(10) # 385
sum_of_powers(10, 3) # 3025
sum_of_powers(10, 3, 5) # 2925

Returns the symmetric difference between two iterables, without filtering out duplicate values

• Create a set from each list.
• Use a list comprehension on each of them to only keep values not contained in the previously created set of the other.

def symmetric_difference(a, b):(_a, _b) = (set(a), set(b))return [item for item in a if item not in _b] + [item for item in b
          if item not in _a]

symmetric_difference([1, 2, 3], [1, 2, 4]) # [3, 4]

Returns the symmetric difference between two lists, after applying the provided function to each list element of both

• Create a set by applying fn to each element in every list.
• Use a list comprehension in combination with fn on each of them to only keep values not contained in the previously created set of the other.

def symmetric_difference_by(a, b, fn):(_a, _b) = (set(map(fn, a)), set(map(fn, b)))return [item for item in a if fn(item) not in _b] + [item
          for item in b if fn(item) not in _a]

from math import floor

symmetric_difference_by([2.1, 1.2], [2.3, 3.4], floor) # [1.2, 3.4]

Returns all elements in a list except for the first one

• Use slice notation to return the last element if the list's length is more than 1.
• Otherwise, return the whole list.

def tail(lst):return lst[1:] if len(lst) > 1 else lst

tail([1, 2, 3]) # [2, 3]
tail([1]) # [1]

Returns a list with n elements removed from the beginning

• Use slice notation to create a slice of the list with n elements taken from the beginning.

def take(itr, n = 1):return itr[:n]

take([1, 2, 3], 5) # [1, 2, 3]
take([1, 2, 3], 0) # []

Returns a list with n elements removed from the end

• Use slice notation to create a slice of the list with n elements taken from the end.

def take_right(itr, n = 1):return itr[-n:]

take_right([1, 2, 3], 2) # [2, 3]
take_right([1, 2, 3]) # [3]

Returns the binary representation of the given number

• Use bin() to convert a given decimal number into its binary equivalent.

def to_binary(n):return bin(n)

to_binary(100) # 0b1100100

Combines two lists into a dictionary, where the elements of the first one serve as the keys and the elements of the second one serve as the values

The values of the first list need to be unique and hashable.

• Use zip() in combination with dict() to combine the values of the two lists into a dictionary.

def to_dictionary(keys, values):return dict(zip(keys, values))

to_dictionary(['a', 'b'], [1, 2]) # { a: 1, b: 2 }

Returns the hexadecimal representation of the given number

• Use hex() to convert a given decimal number into its hexadecimal equivalent.

def to_hex(dec):return hex(dec)